3.2.15 \(\int (\frac {b}{x^4})^{2/3} \, dx\) [115]

Optimal. Leaf size=14 \[ -\frac {3}{5} \left (\frac {b}{x^4}\right )^{2/3} x \]

[Out]

-3/5*(b/x^4)^(2/3)*x

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Rubi [A]
time = 0.00, antiderivative size = 14, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.222, Rules used = {15, 30} \begin {gather*} -\frac {3}{5} x \left (\frac {b}{x^4}\right )^{2/3} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(b/x^4)^(2/3),x]

[Out]

(-3*(b/x^4)^(2/3)*x)/5

Rule 15

Int[(u_.)*((a_.)*(x_)^(n_))^(m_), x_Symbol] :> Dist[a^IntPart[m]*((a*x^n)^FracPart[m]/x^(n*FracPart[m])), Int[
u*x^(m*n), x], x] /; FreeQ[{a, m, n}, x] &&  !IntegerQ[m]

Rule 30

Int[(x_)^(m_.), x_Symbol] :> Simp[x^(m + 1)/(m + 1), x] /; FreeQ[m, x] && NeQ[m, -1]

Rubi steps

\begin {align*} \int \left (\frac {b}{x^4}\right )^{2/3} \, dx &=\left (\left (\frac {b}{x^4}\right )^{2/3} x^{8/3}\right ) \int \frac {1}{x^{8/3}} \, dx\\ &=-\frac {3}{5} \left (\frac {b}{x^4}\right )^{2/3} x\\ \end {align*}

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Mathematica [A]
time = 0.00, size = 14, normalized size = 1.00 \begin {gather*} -\frac {3}{5} \left (\frac {b}{x^4}\right )^{2/3} x \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(b/x^4)^(2/3),x]

[Out]

(-3*(b/x^4)^(2/3)*x)/5

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Maple [A]
time = 0.03, size = 11, normalized size = 0.79

method	result	size
gosper	\(-\frac {3 \left (\frac {b}{x^{4}}\right )^{\frac {2}{3}} x}{5}\)	\(11\)
trager	\(-\frac {3 \left (\frac {b}{x^{4}}\right )^{\frac {2}{3}} x}{5}\)	\(11\)
risch	\(-\frac {3 \left (\frac {b}{x^{4}}\right )^{\frac {2}{3}} x}{5}\)	\(11\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b/x^4)^(2/3),x,method=_RETURNVERBOSE)

[Out]

-3/5*(b/x^4)^(2/3)*x

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Maxima [A]
time = 0.29, size = 10, normalized size = 0.71 \begin {gather*} -\frac {3}{5} \, x \left (\frac {b}{x^{4}}\right )^{\frac {2}{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b/x^4)^(2/3),x, algorithm="maxima")

[Out]

-3/5*x*(b/x^4)^(2/3)

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Fricas [A]
time = 0.35, size = 10, normalized size = 0.71 \begin {gather*} -\frac {3}{5} \, x \left (\frac {b}{x^{4}}\right )^{\frac {2}{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b/x^4)^(2/3),x, algorithm="fricas")

[Out]

-3/5*x*(b/x^4)^(2/3)

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Sympy [A]
time = 0.15, size = 14, normalized size = 1.00 \begin {gather*} - \frac {3 x \left (\frac {b}{x^{4}}\right )^{\frac {2}{3}}}{5} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b/x**4)**(2/3),x)

[Out]

-3*x*(b/x**4)**(2/3)/5

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Giac [A]
time = 1.32, size = 10, normalized size = 0.71 \begin {gather*} -\frac {3}{5} \, x \left (\frac {b}{x^{4}}\right )^{\frac {2}{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b/x^4)^(2/3),x, algorithm="giac")

[Out]

-3/5*x*(b/x^4)^(2/3)

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Mupad [B]
time = 0.92, size = 11, normalized size = 0.79 \begin {gather*} -\frac {3\,b^{2/3}\,x\,{\left (\frac {1}{x^4}\right )}^{2/3}}{5} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b/x^4)^(2/3),x)

[Out]

-(3*b^(2/3)*x*(1/x^4)^(2/3))/5

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